25y^2-6y+1/5=0

Solution for 25y^2-6y+1/5=0 equation:

25y^2-6y+1/5=0

We multiply all the terms by the denominator


25y^2*5-6y*5+1=0

Wy multiply elements

125y^2-30y+1=0

a = 125; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·125·1
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-20}{2*125}=\frac{10}{250}
=1/25
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+20}{2*125}=\frac{50}{250}
=1/5
$